do_shortcode for is_page(slug)

Question

iam new with php and wordpress. i try to implement a shortcode which should only work for a specific slug for my website. all other sites should do another shortcode.

i tryed this:

<?php
if( is_page( ( 'azubi');
     <?php echo do_shortcode( '[contact-form-7 id="274"       title="Bewerbungsformular_beruf" ]' ); ?> 
else
     <?php echo do_shortcode( '[contact-form-7 id="2741"     title="Bewerbungsformular_berufe" ]' ); ?> 

 <?phpendif ?>

but with this i got an error. i thin php syntax is wrong? works this solution for that i want to have?

best regards tom

Answer 1

In this line if( is_page( ( 'azubi'); you start but not end the round bracket ["(" OR ")"] and not used semicolon after the if condition used colon like if( is_page('azubi')):

<?php
if( is_page('azubi')):
     echo do_shortcode( '[contact-form-7 id="274" title="Bewerbungsformular_beruf" ]' ); 
else:
     echo do_shortcode( '[contact-form-7 id="2741" title="Bewerbungsformular_berufe" ]' ); 

endif; 
?>

Check this : https://developer.wordpress.org/reference/functions/is_page/

Enter correct page name.

     if( is_page('About Us')):
                 echo do_shortcode('[contact-form-7 id="263" title="Contact form 1"]');
            else:
                 echo do_shortcode('[contact-form-7 id="264" title="Contact form 1_copy"]');

            endif;