Passing variable as add_shortcode argument

Question

I'm trying to pass a variable into the add_shortcode function to be used as the shortcode name but it does not seem to be working. Is there a way that I can pass a variable similar to this?

foreach ($files1 as $value) {
    $new_value = substr($value, 0, -4);

    add_shortcode($new_value, function() {
        return '<img src="' . PATH . L_ITEMS . $new_value . '.gif">';
    });

}

Answer 1

There are two solutions:

1. Use the third argument for the shortcode.
2. Use the use keyword.

Examples

1. The third parameter for each shortcode callback is the name of the shortcode:

foreach ($files1 as $value) {
    $new_value = substr($value, 0, -4);

    add_shortcode($new_value, function( $attributes, $content, $shortcode ) {
        return '<img src="' . PATH . L_ITEMS . $shortcode . '.gif">';
    });
}

2. Pass the variable you need to the use part of the lambda function:

foreach ($files1 as $value) {
    $new_value = substr($value, 0, -4);

    add_shortcode($new_value, function() use ( $new_value ) {
        return '<img src="' . PATH . L_ITEMS . $new_value . '.gif">';
    });
}

I think you should register just one shortcode and pass the file as attribute value. That would be faster and easier to debug.

Answer 2

I am not sure your mind but I think parameter $new_value you are using in function add_shortcode is undefined.