I want to include my style.css in function.php file?

Question

I'm new to WordPress. I'm including my file using

<link rel='stylesheet' href="<?php bloginfo("stylesheet_url")?>"/>

But if i enqueue my css file in functions.php it is not working. Why? Where is my mistake?

<?php wp_enqueue_style('style',get_template_directory_uri())?>

What is the solution for this?

Answer 1

You are calling the function wrong. You have not given your filename, just a directory.

From the codex

wp_enqueue_style( string $handle, string $src = false, array $deps = array(), string|bool|null $ver = false, string $media = 'all' )

so in your case, you should enqueue like so

add_action( 'wp_enqueue_scripts', 'wpse_my_style' );
function wpse_my_style(){
  wp_enqueue_style( 'my-style', get_stylesheet_directory_uri() . 'path/to/your/css' );
}    

the rest of the parameters are optional

Answer 2

function wpdocs_style() {
wp_enqueue_style( 'style-name', get_stylesheet_uri() );  //This is for getting style.css of current theme
wp_enqueue_style( 'style-name1', get_teplate_directory_uri() . '/css/custom.css', array('jquery') );   //This is for getting other css file from parent directory  
wp_enqueue_script( 'script-name1', get_teplate_directory_uri() . '/js/custom.js', array('jquery') );   //This is for getting JS file from parent directory  
}
add_action( 'wp_enqueue_scripts', 'wpdocs_style' );
             OR
//Or as an laternate you can hook with wp_head also
add_action( 'wp_head', 'wpdocs_style' );

In order to run the above function need to add <?php wp_enqueue_script("jquery"); ?> (If you use this action add_action( 'wp_enqueue_scripts', 'wpdocs_style' );) in header.php befor </head>.

You have to assign name to every style (like I assign style-name, style-name1 etc) and name should be unique. And if you want to qnqueue from child theme's functions.php then you have to use get_stylesheet_directory_uri() instead of get_teplate_directory_uri().