PHP Output also in Child theme, but different

Question

I have a multilingual site setup: www.jeroenbrugman.com

The main dutch version uses Fluxus. On the artwork page I output a link using this from Functions.php

function prefix_term_name($terms, $post_id, $taxonomy ) {
  foreach ($terms as &$term) {
    $term->name = 'Terug naar '.$term->name;
  }
}
  return $terms;

And on the page itself I show it using this:

 <h3 class="widget-title">
                                <?php
  add_filter( 'get_the_terms','prefix_term_name',10,3);
  the_terms($post->ID, 'fluxus-project-type'); 
  remove_filter( 'get_the_terms','prefix_term_name',10,3); ?>
                                <a href="../"><?php the_terms($post->ID, 'fluxus-project-type'); ?></a></h3>

But, on my English page. I need to output the 'Terug naar' from the main theme function.php as: 'Back To'. but when I copy the code from main functions.php to my child theme's functions.php and change Terug naar to Back to the whole english site goes blank.

What am I doing wrong?

Kind regards

Answer 1

You need to make the function pluggable, that means, to support child themes, the functions in parent theme should use:

if ( !function_exists( 'function_name' )) {
    function function_name() {
        //Stuffs
    }
}  

You should have seen a PHP Error message if you have debugging enabled.

EDIT: The below code snippet if to answer your other question in comment.

function modify_read_more_link() {
    global $post;

    return '<a class="more-link" href="' . get_permalink( $post->ID ) . '">Your Read More Link Text</a>';

}
add_filter( 'the_content_more_link', 'modify_read_more_link' );

Answer 2

Issue Fixed!

Had to wrap my function with

if ( !function_exists( 'function_name' )) {
    function function_name() {
        //Stuffs
    }
}  

Perfect!