3

There are a lot of answers on how to count users posts by using:

<?php
    if ( is_user_logged_in() ) {
        global $wpdb;
    $user = wp_get_current_user();
    $where = get_posts_by_author_sql( 'page', true, $user->ID );
    $count = $wpdb->get_var( "SELECT COUNT(*) FROM $wpdb->posts $where" ); ?>

//option 1
<h2>Hey <?php echo $current_user->display_name ?>, check your page here: {page title with link to page} </h2>

<?php } else { ?>
//option 2
<h2>Welcome <?php echo $current_user->display_name ?>, etc.. text with tags etc.</h2>

<?php } } else { ?>
//option 3
<h2>text with tags etc.</h2>

<?php } ?>

But since users can also create pages, how does one get the count of current user's pages in a similar situation as the code above?

1 Answer 1

3

Look what count_user_posts() does inside and change the post type parameter:

global $wpdb;
// 'page' is the important part here
$where = get_posts_by_author_sql('page', true, $userid);
$count = $wpdb->get_var( "SELECT COUNT(*) FROM $wpdb->posts $where" );

Then you change your snippet to:

global $wpdb;
$user = wp_get_current_user();
$where = get_posts_by_author_sql( 'page', true, $user->ID );
$count = $wpdb->get_var( "SELECT COUNT(*) FROM $wpdb->posts $where" );

if ( $count >= 1 ) {

    // echo your text snippet

} else {

    // echo your form

}
7
  • Hi Tosho, can you please also explain how to add that code in the above example?
    – tobe
    Commented Apr 19, 2013 at 14:58
  • @tobe See my update. Caveat: I haven’t tested it.
    – fuxia
    Commented Apr 19, 2013 at 15:04
  • Great! it works like a charme!
    – tobe
    Commented Apr 19, 2013 at 17:47
  • Hi Toscho, what if I would like to display the page title of that user with link to that page?
    – tobe
    Commented Apr 24, 2013 at 7:55
  • @tobe See my update, just an idea, not tested.
    – fuxia
    Commented Apr 24, 2013 at 8:07

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