New answers tagged json
1
This seems more like a PHP programming question, but yes as you guessed in PHP if you want the value of a variable you just need $var. echo $var outputs it and will cause a syntax error how you've used it.
Otherwise everything else looks ok, although obviously I can't say if that data structure will give you valid JSON-LD ;-)
EDIT: Also it's good to give ...
0
Try following way
....................
URL: /wp-json/wp/v2/posts?_embed
image: json["_embedded"]["wp:featuredmedia"][0]["source_url"],
It's working fine.try
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