I can't find the rights arguments to display only one post of a category when I click on a div. I call the post with Ajax and I display it in a div popup.Perhaps these arguments are not sufficient, or the problem come from another part?But when I echo the get_the_id in the loop it is the correct id of the post.However, it displays all posts in category. Another problem, if I don't specify a category (name or id) it display all posts of my Wordpress.These two problems come only when I call posts in Ajax.

function more_content() {

    $the_post_id = the_ID(); // $_POST['the_ID'];
    $args = array(
        'post_type' => 'post',
        'category_name' => 'materials',
        'p' => $the_post_id


    $ajax_query = new WP_Query($args);

    if ( $ajax_query->have_posts() ) : while ( $ajax_query->have_posts() ) : $ajax_query->the_post();

          $the_excerpt = the_excerpt();
          $the_content = the_content();

    echo $the_excerpt;
  echo "<div style='color:white; font-size:40px;'>",$the_post_id,"</div>";
    echo $the_content;


  • Is the category a subcategory (or child category)? If so, see developer.wordpress.org/reference/functions/query_posts/… Sep 4, 2019 at 10:21
  • it's a category (not a subcategory, not a child category). I think the main problem doesn't come with the category, even if it's not normal to define a category to display a unique post. the code above is the functions.php file. Do you think the problem could come from other file ex : ajaxcall.js ?
    – Rak Arthus
    Sep 4, 2019 at 10:40

1 Answer 1


I am pretty sure that the Category parameters cannot be combined with p. In the documentation it says: "Show posts associated with certain categories." and none of the examples combine a category with a single post like you are trying to do.

Instead I think you need to use a taxonomy query as such:

$args = [
    'post_type' => 'post', 
    'tax_query' => [

Give that a try and remember to mark this as the answer if it solves your problem.

Also, be sure you are getting the right ID. In the code sample you provided, the_ID() is definitely not what you want. the_ID() echos the value of the ID to the output. What you probably want instead is get_the_ID() but even that will be wrong in this context (retrieving a single post by ID as defined by the input coming from the GET request).

And also, if you are plucking the ID from $_POST or $_GET, be sure to sanitize it prior to using it in your query (although, I'm pretty sure WordPress also sanitizes input prior to running the query, you can never be too safe).

  • The result is the same. I have try with "get_post" (to get my post without a loop) and with global "Wp_query" but i'm not sure to write the correct code. I handed the right code for the ID $_POST['the_ID']; // the_ID(); and I have add this code in my loop : echo "<p class='col-white font-size-2rem font-weight-bolder'>",$the_post_id,"<p>"; that display me the id corresponding of each post . Currently I have two post for the test. When I call in ajax my post for popup clicking in list one of my two posts the link of post displaying in the browser is the right id of this post.
    – Rak Arthus
    Sep 4, 2019 at 16:42
  • I noticed that my callajax.js seems to be wrong because I can't get the id of the post with an "alert" and I get "undefined" result. my jquery code :
    – Rak Arthus
    Sep 4, 2019 at 16:44
  • jQuery(document).ready(function(){ jQuery('.post-link').click(function() { var post_id = jQuery(this).data('id'); jQuery.post( ajaxurl, { 'action': 'more_content', 'the_ID': post_id }, function(response){ // on affiche la réponse ou l'on veut jQuery('#more-content').html(response); } ); alert (post_id); return false; }); jQuery(".close-more").click(function(){ jQuery('#more-content').html(''); }); });
    – Rak Arthus
    Sep 4, 2019 at 16:44
  • I invite you to check out wp-cli.org The tool includes a WordPress "shell" that allows you to test code just by typing it into a terminal. Using that tool, you can easily test your code until you are happy with how it works. I would start implementing the code by making it work outside of ajax first, and then, following the principles of Progressive Enhancement, make it work through ajax. Without a complete code example it is very difficult for us to provide a concrete answer. Sep 5, 2019 at 16:02
  • The answer of my question : Hi. my problem is resolved. I have replaced in callajax.js jQuery(this).data('id'); by jQuery(this).attr('id'); and add inside html page : id=",the_ID()," . Also I removed : 'category_name' => 'materials', thanks for your help
    – Rak Arthus
    Sep 5, 2019 at 16:27

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