I want to use a variable inside the function wp_enqueue_style(), right now the only way i figure out to do so is to define a constant but it needs to be variable

 define( 'NAME', 'mystyle' );
 wp_enqueue_style(NAME .'-style', ABS_URL . /includes/box.css' , false ); 

How could I add that variable to this function ? I tried this and it doesnt work, any insights on this?

 wp_enqueue_style($name .'-style', ABS_URL . /includes/box.css' , false ); 
  • In what way did it not work?
    – janh
    Nov 2, 2017 at 22:00
  • the variable $name is empty, it calls the box.css style but the id is "-style-css" instead of "mystyle-style-css" Nov 2, 2017 at 23:32
  • Is that the actual code? I can’t see any reason it wouldn’t work. Nov 3, 2017 at 0:33
  • How could $name be empty if you set it with $name="mystyle" just in the previous line?
    – janh
    Nov 3, 2017 at 22:14

1 Answer 1


this syntax doesn't seem right to me.

First of all what is ABS_URL? If it's a constant that you've defined earlier, then there is an ' missing before /includes/box.css'. The code should look like this:

$name = 'mystyle';
wp_enqueue_style( $name .'-style', ABS_URL . '/includes/box.css', false );

It works as it should, the output is: <link rel='stylesheet' id='mystyle-style-css' href='whatever-there-is-in-ABS_URL-constant' type='text/css' media='all' />

Also, make sure if you need to define this constant at all - if you want to load stylesheet from your theme's folder or its subfolders, use get_stylesheet_directory_uri() function:

$name = 'mystyle';
wp_enqueue_style( $name .'-style', esc_url( get_stylesheet_directory_uri() ) . '/includes/box.css' , false ); 
  • yeah, it was something really dumb, i didnt pass that variabe as an argument because the wp_enqueue_style was inside a function Nov 4, 2017 at 15:26

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