4

My loop below shows the latest 4 posts from the same category as the post currently being viewed. Its located within single.php.

I'm trying to get the URL of that same category so I can link back to category.php to view all posts from that same category. I thought grabbing the category slug would work but my code below doesn't output anything:

<?php
global $post;
$categories = get_the_category();

    foreach ($categories as $category) :

       $exclude = get_the_ID();
       $posts = get_posts('posts_per_page=4&category='. $category->term_id);

        foreach($posts as $post) :
         if( $exclude != get_the_ID() ) { ?>

                <a href="<?php the_permalink(); ?>" title="<?php the_title(); ?>" class="post c-1"> Link to actual post</a>

    <?php } endforeach; ?>

<a href="<?php bloginfo('url'); ?>/categories/<?php echo $childcat->cat_slug; ?>" title="View all" class="btn border"><i class="i-right-double-arrow"></i> View all <?php echo $childcat->cat_slug; ?></a>
<?php  endforeach; wp_reset_postdata(); ?>
5

Use:

get_category_link( $category_id );

See:

https://codex.wordpress.org/Function_Reference/get_category_link

In your specific case:

<?php
global $post;
$categories = get_the_category();

    foreach ($categories as $category) :

       $exclude = get_the_ID();
       $posts = get_posts('posts_per_page=4&category='. $category->term_id);

        foreach($posts as $post) :
         if( $exclude != get_the_ID() ) { ?>

                <a href="<?php the_permalink(); ?>" title="<?php the_title(); ?>" class="post c-1"> Link to actual post</a>

    <?php } endforeach; ?>

<a href="<?php echo esc_url( get_category_link( $category->term_id ) ); ?>" title="View all" class="btn border"><i class="i-right-double-arrow"></i> View all <?php echo $category->name; ?></a>
<?php  endforeach; wp_reset_postdata(); ?>

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.