The following code works fine for me:
$term = get_term_by('slug', ‘foo’, 'post_tag');
$args = array (
'posts_per_page' => 5,
'paged' => $paged,
'post__not_in' => get_option( 'sticky_posts' ) ,
'tag__not_in' => $term
);
I'd now like to get_term_by multiple tags, e.g., 'foo' and 'bar' (I'm trying to display all posts except those tagged 'foo' or 'bar').
I realize this is probably elementary, but I'm not sure how to go about it.
Ideas?
I've come up with a better way than in my previous answer:
First you need to set up an array containing the slugs of the tags you want to exclude. Then loop over that array, and on each term, use get_term_by() to get the tag, saving its ID to another array. That is what you can pass through to your query.
$tag_slugs = array(
'foo',
'bar',
);
$tag_ids = array();
foreach( $tag_slugs as $slug ) {
$tag = get_term_by( 'slug', $slug, 'post_tag' );
$tag_ids[] = $tag->term_id;
}
$args = array (
'posts_per_page' => 5,
'paged' => $paged,
'post__not_in' => get_option( 'sticky_posts' ),
'tag__not_in' => $tag_ids,
);
get_term_by() can only retrieve a single term. Try using get_terms() instead. http://codex.wordpress.org/Function_Reference/get_terms
