How do we exclude multiple pages (like opposite of is_page)

Question

Scenario

I have a following customized format for the website with Woocommerce.

1. <?php if(is_shop()) {?> There are certain css styles, JS options used for this particular page
2. <?php } if(is_front_page()) { ?> Same as above with different css animations used or certain classes when on home page of the site

Question

Now, I want to use some specific jQuery options such as .Delay(), Hide(), & Show() on pages other than Shop & Home page

However, If I simply add the jQuery outside the options 1 & 2 mentioned above .. this gets applied to entire website -- overriding options specified for is_shop

I think if we can exclude pages then I can exclude these 2 pages above. Writing is_page (array) would be too tedious for hundreds of pages.

How can we exclude certain WP pages (in my case only 2)? Or should I re-format the page using if else & will it work?

Thanks in advance.

Answer 1

The opposite of is_page() will be ! is_page(). In php the ! is used as negative, so ! is_page( 42 ) will means something like

if we are not on page ID 42, do something, in other words exclude page ID 42

Answer 2

Thanks Pieter, that solved the issue. I'm writing below some details just in case someone comes here in future.

As stated by Pieter in answer above, using !is_page is for excluding the page in opposite of using is_page for including functions for that page.

In my case, I noticed two things.

1. <?php if(!is_shop() && (!is_front_page())) {?> I used the code needed everywhere else other than these 2 pages. Works great
2. All the jQuery options needs to be common in all cases to work. We cannot ignore it in any of the cases. Which means, I had to mention jQuery options in all three cases to make it work as desired.

In my example: I had is_shop(), is_front_page() & !is_shop() where each of them needed this jQuery("#primary").delay($value) for it to work as desired on all pages.

Thanks all.