How can I check to see if the current logged-in user is an administrator or an editor?

I know how to do each individually:

<?php if(current_user_can('editor')) { ?> 
    <!-- Stuff here for editors -->
<?php } ?>

<?php if(current_user_can('administrator')) { ?>
    <!-- Stuff here for administrators -->
<?php } ?>

But how do I work those in together? I.e., the user is an administrator or editor?

  • 10
    if( current_user_can('editor') || current_user_can('administrator') ) – Shazzad Jan 30 '14 at 14:10

First answer, not WordPress-related because it is just only PHP: Use the logic "OR" operator:

<?php if( current_user_can('editor') || current_user_can('administrator') ) {  ?>
    // Stuff here for administrators or editors
<?php } ?>

If you want to check more than two roles, you can check if the roles of the current user is inside an array of roles, something like:

$user = wp_get_current_user();
$allowed_roles = array('editor', 'administrator', 'author');
<?php if( array_intersect($allowed_roles, $user->roles ) ) {  ?>
   // Stuff here for allowed roles
<?php } ?>

However, current_user_can can be used not only with users' role name, but also with capabilities.

So, once both editors and administrators can edit pages, your life can be easier checking for those capabilities:

<?php if( current_user_can('edit_others_pages') ) {  ?>
    // Stuff here for user roles that can edit pages: editors and administrators
<?php } ?>

Have a look here for more information on capabilities.

| improve this answer | |
  • 1
    do you need to check if is_logged_in(); ? – RobBenz May 1 '17 at 11:09
  • 3
    @RobBenz no, in any of the cases. Because current_user_can() always returns false if the user is not logged in, and wp_get_current_user() will return an user without any role if the user is not logged in, so the array_intersect() will always be false. – gmazzap May 1 '17 at 18:46
  • 2
    In the PHPDoc of the current_user_can() function, we can see the line "While checking against particular roles in place of a capability is supported in part, this practice is discouraged as it may produce unreliable results". So I think it would be better to avoid using roles while checking for a user's capability :-) – Erenor Paz Sep 1 '17 at 9:58
  • When I use the array_intersect method, I get a PHP warning in our server error log saying array_intersect(): Argument #2 is not an array. Is this because the user(s) it's checking only have one Role? – Garconis Jan 23 '18 at 14:44
  • @Garconis normally it should be an array. For some reason it seems for you is not an array. array_intersect($allowed_roles, (array)$user->roles ) will work with no issues. – gmazzap Jan 25 '18 at 7:02

First, current_user_can() should not be used to check a user's role - it should be used to check if a user has a specific capability.

Second, rather than being concerned with the user's role but instead focusing on capabilities, you don't have to bother with doing things like the problem asked about in the original question (which is checking if the user is an administrator OR an editor). Instead, if current_user_can() was being used as intended, which is to check for a user's capabilities, not their role, you wouldn't need the conditional check to contain an "or" (||) test. For example:

if ( current_user_can( 'edit_pages' ) ) { ...

edit_pages is a capability of both administrator and editor roles, but not any lower roles such as authors. This is how current_user_can() was intended to be used.

| improve this answer | |
  • 2
    Please note: High level WP devs agree with this answer. You should try to avoid role checking as much as possible, use capabilties. I'm currently working on a project with multiple roles that only have the 'read' cap. The only solution is role checking for me. Sorry, I can't find the link, it was an open discussion on the WP Github. – Bjorn Apr 26 '19 at 21:44
  • 1
    This should be the accepted answer, IMO. current_user_can should generally be used for capabilities, not roles. – Armstrongest May 13 '19 at 21:43
  • +1 to this, avoid checking roles via current_user_can(). If you want to check roles by key then perform a role check instead of a cap check :) – William Patton Mar 5 at 11:43
  • What is the proper function then, for checking user roles explicitly & safely? It seems, it's a bit hard to find that (if exists). @Bjorn – Viktor Borítás Apr 15 at 8:26
  • 1
    @Viktor Borítás There are multiple valid solutions on this page. But only use them if current_user_can() is not an option. Also, my comment is more security based. For example, if you want to restrict content for specific users in most cases a capability check is sufficient for this task. – Bjorn Apr 16 at 13:21

As @butlerblog reply stated, you should not use current_user_can to check against a role

This notice is specifically added in the PHP documentation of has_cap function which is called by current_user_can

While checking against a role in place of a capability is supported in part, this practice is discouraged as it may produce unreliable results.

The CORRECT way to do this is to get the user and check the $user->roles, like this:

if( ! function_exists( 'current_user_has_role' ) ){
    function current_user_has_role( $role ) {

        $user = get_userdata( get_current_user_id() );
        if( ! $user || ! $user->roles ){
            return false;

        if( is_array( $role ) ){
            return array_intersect( $role, (array) $user->roles ) ? true : false;

        return in_array( $role, (array) $user->roles );

Here's some helper functions I use to do this (as sometimes i don't want just current user):

if( ! function_exists( 'current_user_has_role' ) ){
    function current_user_has_role( $role ){
        return user_has_role_by_user_id( get_current_user_id(), $role );

if( ! function_exists( 'get_user_roles_by_user_id' ) ){
    function get_user_roles_by_user_id( $user_id ) {
        $user = get_userdata( $user_id );
        return empty( $user ) ? array() : $user->roles;

if( ! function_exists( 'user_has_role_by_user_id' ) ){
    function user_has_role_by_user_id( $user_id, $role ) {

        $user_roles = get_user_roles_by_user_id( $user_id );

        if( is_array( $role ) ){
            return array_intersect( $role, $user_roles ) ? true : false;

        return in_array( $role, $user_roles );

Then you can just do this:

current_user_has_role( 'editor' );


current_user_has_role( array( 'editor', 'administrator' ) );

| improve this answer | |
<?php if( current_user_can('editor')) :
  echo "welcome";
elseif( current_user_can('member')) :
  echo "welcome";
else :
 wp_die("<h2>To view this page you must first <a href='". wp_login_url(get_permalink()) ."' title='Login'>log in</a></h2>");
| improve this answer | |
  • 1
    It would be great if you could explain as how it helps OP. – bravokeyl Sep 29 '16 at 17:32
  • You can allow to see the page only "editor" or "member" you can post this code direct in generic-page.php – seowmx Sep 29 '16 at 17:36
  • 5
    Please don't just drop code. Add comments and some explanation how this solves the askers problem. – kraftner Sep 29 '16 at 18:09
  • So your answer is code duplication for each role? – Julix Oct 22 '19 at 17:20

The correct answers to the above solution-question are by else programming basic:

if( current_user_can('administrator')) { 

<!-- only administrator will see this message -->

} else { 

        if( wp_get_current_user('editor')) {

<!-- only editor but no administrator will see this message -->

<style type="text/css">#perhapsDIVremovalidentifier{
} else {

<!-- the user is neither editor or administrator -->


Brief: The administrator is found, but if we push editor the administrator is as well found. So we just let the administrator pass through and identify the editor only.

Remember you should always use this code to call that above to minimize cpu code usage:

| improve this answer | |
  • That is exactly what is stated in the question, and what the author doesn't want. – fuxia Jun 3 at 21:15
  • I've added brief so that we have no misunderstanding. It was hard to follow the else rules I believe. – Dealazer Jun 4 at 8:52

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