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Ok I didn't find an answer yet.. because my code is different.. I want to set the featured image as the div's background but I don't know how to do that.. html, php and css collide in one line.. This is the div..

echo '<div id = "circ"><ul><li><a href = "';
the_permalink(); echo '">'; '</a></li></ul></div>'; ?>

and this is the code I want..

 $src = wp_get_attachment_image_src ( get_post_thumbnail_id('thumbnail'));


<div id = "circ" style="background: url(<?php echo $src[0]; ?> ) !important;">test</div>

I could have inserted it in one line like this

echo '<div id = "circ" style="background: url(<?php echo $src[0];><ul><li><a href = "';
the_permalink(); echo '">'; '</a></li></ul></div>'; 

but then they all collide which I don't know the workaround for it..

  • What do you mean by "collide in one line"? Also, this is looking like a pure PHP problem to me. – s_ha_dum Jan 18 '14 at 15:42
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    for the function get_post_thumbnail_id, the argument should be post_id (interger), but you have given size attribute thumbnail. you can completely remove 'thumbnail' from the function, it should work then – Shazzad Jan 18 '14 at 16:18
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You're code is not working as you have an echo within an echo, try this code (not tested)

<?php
echo '<div id = "circ" style="background: url('.$src[0].'><ul><li><a href = "'.the_permalink().'</a></li></ul></div>';
?>

If you're echo'ing something and then you want to add php within that echo you need to break the echo by adding '. $variable .'

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