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I am using a redirection plugin and want to redirect the existing search url

http://www.example.com/search/abcdef to http://www.example.com/?s=abcd

I am able to redirect /search/abcdef to /?s=abcdef however I can't get hold of how to trim and use the first of characters of search term i.e abcd in short it should look like /?s=abcd

As of now I am using following regex with plugin:

Source URL - /search/(.*)

Target URL - http://www.example.com/?s=$1

I'd appreciate any pointers in that direction or maybe a working answer ;)

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    How are you redirecting? There are already close votes on this question for being off-topic and I am tempted to add one unless I see some valid WordPress components. – s_ha_dum Sep 24 '13 at 15:09
  • Maybe I am not being clear as to what I want. Here's the plugin I am using for handling redirection - wordpress.org/plugins/redirection As already mentioned above, I have already modified the "/search/abcdef" part of url to match that of wordpress inbuilt search mechanism. What I am trying to accomplish here is to extract first 4 characters of "abcdef" and use it with "/?s=" parameter. I hope it makes some sense now. – Paritosh Sep 24 '13 at 16:28
  • Please don't comment, but add that as edit instead. – kaiser Sep 29 '13 at 6:25
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No need for a Regex. There's substr( $string, int $offset ); built into PHP to achieve that.

  • True. But I am specifically looking out for a regex to achieve the same since the plugin I am using (Redirection) requires regex. – Paritosh Sep 24 '13 at 14:42
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    @Paritosh So Google was no option? ... ^[a-zA-Z0-9]{4}$ for alphanumeric first four characters... – kaiser Sep 24 '13 at 14:45
  • Yes, it was and is an option but I can't find a related topic. String matching results dominate my queries. Hence the thought of posting here :) – Paritosh Sep 24 '13 at 14:48
  • @Paritosh What I showed you in above comment (the working Regex), was extracted from the first search result in above linked Google search results page ;) – kaiser Sep 24 '13 at 14:50
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    Are you serious, @Paritosh ? You've now gotten an analogous function as well as a regex. – Johannes Pille Sep 24 '13 at 15:06

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