Hide specific taxonomies from a taxonomy list using 'get_object_taxonomies'

Question

Hello,

I have a 'Custom Post Type' with 8 taxonomies and I'm pretending display a list with only 6 taxonomies and the no empties terms of each one and hide 2 taxonomies.

My current code displays all taxonomies with all terms hiding the empties one but I can not get how to hide the two taxonomies I want.

This is my code:

 <? php
  $args = array(
    'public'   => true,
    '_builtin' => false
    );
  // $output = 'names'; // or objects
  // $operator = 'and'; // 'and' or 'or'
  // $taxonomies = get_taxonomies( $args, $output, $operator );
  $object = 'my-cpt-name';
  $output = 'names';
  $taxonomies = get_object_taxonomies( $object, $output );
  if ( $taxonomies ) {
    foreach ( $taxonomies  as $taxonomy ) {
      echo '<h3>' . $taxonomy . '</h3>';

      $args = array( 'hide_empty=0' );

      $terms = get_terms( $taxonomy, $args );
      if ( ! empty( $terms ) && ! is_wp_error( $terms ) ) {
         $count = count( $terms );
         $i = 0;
         $term_list = '<ul class="term-list">';
         foreach ( $terms as $term ) {
             $i++;
             $term_list .= '<li><a href="' . esc_url( get_term_link( $term ) ) . '" >' . $term->name . '</a></li>';
             if ( $count != $i ) {
             }
             else {
                 $term_list .= '</ul>';
             }
         }
         echo $term_list;
      }
    }
  }
?>

I have set up the 'public' taxonomy $arg as 'false' but doesn't work.

$args = array(
    'labels'                     => $labels,
    'hierarchical'               => true,
    'public'                     => false,
    'show_ui'                    => true,
    'show_admin_column'          => true,
    'show_in_nav_menus'          => true,
    'show_tagcloud'              => true,
);

And also, how could I display the taxonomy name instead of the taxonomy slug on echo '<h3>' . $taxonomy . '</h3>';

Answer 1

Try this:

<?php
$object = 'post';
$output = 'objects';
$taxonomies = get_object_taxonomies( $object, $output );
$exclude = array( 'post_tag', 'post_format' );

if ( $taxonomies ) {

    foreach ( $taxonomies  as $taxonomy ) {

        if( in_array( $taxonomy->name, $exclude ) ) {
            continue;
        }

        $terms = get_terms( array(
            'taxonomy' => $taxonomy->name,
            'hide_empty' => true,
        ) );

        if ( ! empty( $terms ) && ! is_wp_error( $terms ) ) {

            echo '<h3>' . $taxonomy->label . '</h3>';   

            $term_list = '<ul class="term-list">';

            foreach ( $terms as $term ) {
                $term_list .= '<li><a href="' . esc_url( get_term_link( $term ) ) . '" >' . $term->name . '</a></li>';          
            }

            $term_list .= '</ul>';

            echo $term_list;
        }

    }

}
?>

For this example I set up some parameters:

• Post type we're searching on: $object = 'post';
• Taxonomies we want to exclude: $exclude = array( 'post_tag', 'post_format' );

Then we get all associated taxonomies and loop through them. While we loop through them, we check each taxonomy against our exclude array and skip it if applicable.

Then we grab all the terms from each taxonomy and build list of links.

Answer 2

@darrinb

I have solved the problem. Your code helped me a lot although had a error. :)

The error was getting the 'terms':

$terms = get_terms( array(
            'taxonomy' => $taxonomy->name,
            'hide_empty' => true,
        ) );

Following the codex:

The correct way is the following:

$arg = array(
        'hide_empty' => true,
        );
$terms = get_terms($taxonomy->name, $arg );

Thank you!