Using functions concatenated with strings inside a variable

Question

Trying to do some dynamic image sourcing but I'm stuck. Probably pretty basic stuff, but I'm new to this.

This works:

<img src="<?php  bloginfo('template_url');?>/images/LakeArnaulMap-<?php the_ID();?>.png"/>

Why doesnt this:

<?php 
$my_img = '<img src="' . bloginfo('template_url') . '/images/MyImage' . the_ID() . '.png"/>';
echo $my_img;
?>

Answer 1

bloginfo echoes the output in place. If you look at the source you will see that template_url is not where you expect it to be.

Use get_bloginfo instead, or even better use get_stylesheet_directory