Displaying Current Page Number Conditionally

Question

I want to display the current page number in the site. I want it to be conditional though so that it doesn't show up on the home/front page. Using the code below, the page number is being displayed at all.

<?php 
    $pageNumber = (get_query_var('paged')) ? get_query_var('paged') : 1;
    if(!is_front_page()) {
        echo "<div class='page-count'><?php echo '&ndash; $pageNumber &ndash;'; ?></div>";
    }
?>

Answer 1

You want to use is_paged which checks if the current page number is 2 or above (and returns true if it is). is_front_page checks 'if the main page is a posts or a Page'.

You've also used incorrect syntax (changed from a double quote to a single quote, and used <?php inside a string being echoed).

Untested, but the following should do what you want:

<?php 
    $pageNumber = (get_query_var('paged')) ? get_query_var('paged') : 1;
    if(is_paged()) {
        echo "<div class='page-count'> &ndash;".$pageNumber." &ndash;</div>";
    }
?>

Answer 2

as get_query_var('paged') returns empty on the first page, this might work as well (untested):

<?php
  if( get_query_var('paged') ) echo "<div class='page-count'> &ndash;".get_query_var('paged')." &ndash;</div>";
?>