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I have a code which needs a variable compare string

        'key' => 'rob_value',
        'value' => $rob,
        'compare' => '='   

the compare =>'=' needs to be '=' to get values according a variable data from search form, but sometimes the value is null (empty) and the compare line needs to change to compare =>'!='

I have tested changing the code manually and it works perfectly. Now I want to do the code change according the values on search form.

share|improve this question
where is problem? – Alexey Nov 24 '11 at 0:16
@Alexey the compare line now is '=',and I need the line changes automatically to '!=' value.... something like if $rob="" then $rob_comp="!=" else $rob_comp="=" then we got to array to use 'compare'=>$rob_comp instead '=' or '!=' only. – Fernando Baltazar Nov 24 '11 at 0:38
Just change it! I don't see a problem. How can I help you? – Alexey Nov 24 '11 at 1:14
I found the anwser to my last 3 questions the meta_query works perfect! first I need to do this: php if($rob != '') { $rob_comp= '='; } else { $rob_comp= '!='; } then change the code for array array( 'key' => 'rob_value', 'value' => $rob, 'compare' => $rob_comp ) Doing this works for more than 2 meta_query with no need to do a wpdb=>query – Fernando Baltazar Nov 24 '11 at 1:51
Please add this as an answer and accept it. – Rutwick Gangurde Nov 24 '11 at 3:43

Use a ternary operation to keep it trim.

    'key' => 'rob_value', 
    'value' => $rob, 
    'compare' => ( empty( $rob ) ? '!=' : '=' )

Breakdown, incase you've not seen ternary operators before..

    'key' => 'rob_value', 
    'value' => $rob, 
    'compare' => ( 
        // If
        empty( $rob ) 
        // Then
        ? '!=' 
        // Else
        : '=' 


FYI: This question should ideally have been on StackOverflow, it's more centric to general PHP(if/else/comparison) than to WordPress(you just happening to be writing code for WordPress).

All the same, hope that helps..

share|improve this answer
thanks for this example, I wrote the if operators outside the query to use an extra $string... but this code is easier to follow. This also helps to close this answer, Thanks to all! – Fernando Baltazar Nov 30 '11 at 7:48
@FernandoBaltazar please come back and accept this answer if it solves your problem. – Chip Bennett Feb 14 '12 at 17:20

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