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Im using the get_users function to show a custom list of users on the site. The only issue Im having a problem figuring out now is how to paginate the result.

This is a sample of the function that Im using:

Sample Code Screen shot

There doesn't seem to be an obvious way of creating a pagination for the this function. I would appreciate some help with this.

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1 Answer 1

First get the total number of users:

$total_users = count_users();
$total_users = $total_users['total_users'];

and the current page:

$paged = get_query_var('paged');

Set a variable that will decide how many users to display per page:

$number = 20; // ie. 20 users page page 

Then, in your $args array add the offset if the current page != 0, and the max number of users to return:

'offset' => $paged ? ($paged * $number) : 0,
'number' => $number,

Now add your code from above, and create the page links:

// display the user list here

if($total_users > $number){

  $pl_args = array(
     'base'     => add_query_arg('paged','%#%'),
     'format'   => '',
     'total'    => floor($total_users / $number),
     'current'  => max(1, $paged),
  );

  // for ".../page/n"
  if($GLOBALS['wp_rewrite']->using_permalinks())
    $pl_args['base'] = user_trailingslashit(trailingslashit(get_pagenum_link(1)).'page/%#%/', 'paged');

  echo paginate_links($pl_args);
}

See paginate_links() for a full list of arguments....

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1  
This was awesome and pointed me in the right direction, but it removes the second page of results how it was originally set up. Mainly $pl_args['total'] should be "ceil" not "floor" since it is the total pages. And then 'offset' for the get_user $args should be 'offset' => $paged ? ($paged-1) * $number : 0,. You need to remove 1 from $paged to get 0,1,2,3 instead of 0,2,3,4. –  Jake Nov 11 '13 at 18:51

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