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I want to link content comprised of a custom field(field1_details) using another custom field(field2_link) which is a URL type. the_field('field1_details') is text_area field and get_field('field2_link') is a website field (using a ACF addon).

(These custom fields are created using Advanced custom fields plugin)

Here is the code I am trying in loop.php:

<span class="c_f"><a href="<?php get_field('field2_link'); ?>"><?php if( function_exists('the_field') ) the_field('field1_details'); ?></a></span>


 <a href="">The text content</a> ( Doesn't out put the link)

And tried this without the if

<span class="c_f"><a href="<?php get_field('field2_link'); ?>"><?php the_field('field1_details'); ?></a></span>

Trying with the_field instead of get_field

<span class="c_f"><a href="<?php the_field('field2_link'); ?>"><?php the_field('field1_details'); ?></a></span>


<span><a href="&lt;a href=" http:="" google.com"="" target="_blank">google.com</a>"&gt;This is the test content</span>


The two custom fields works fine if I use them separately like this:

Field 1- field1_details

Output HTML-

<div class="field-wrap"><span class="field icon-edit">This is the Text

Field 2- field2_link

or without the if

<span class="link-field"><?php the_field('field2_link'); ?></span>

Out put-

 <span class="link-field"><a href="http://google.com"

I think I am not using it in a right way. Could any one tell me how to link the field with a URL entered in the another field in loop.php?

Also tell me how would you do it in the functions.php instead of the templates like loop.php

share|improve this question
Why have you included the if clause? – Wrought_steel Jan 24 '14 at 5:32
if( function_exists('the_field') ) checks if the ACF function exists. – IamSJ Jan 24 '14 at 5:36
I'm still unsure why you would check (and not check get_field), but you seem to have some syntax problems. Shouldn't it be if( function_exists('the_field') ) {the_field('field1_details')} ? – Wrought_steel Jan 24 '14 at 5:41
I have tried with out the if. But no change. – IamSJ Jan 24 '14 at 5:58
What is it showing? Can you isolate to see if the problem is the field2_link or the field1_details function? – Wrought_steel Jan 24 '14 at 6:05

According to the documentation, you should display a field like:

<p><?php the_field('field_name'); ?></p>

Change your get_field to the_field:

<span class="c_f"><a href="<?php the_field('field2_link'); ?>"><?php the_field('field1_details'); ?></a></span>
share|improve this answer
I have already tried the_field. But the link is broken. <?php the_field('field_name'); ?> is used to publish the field as it is. I don't know how to make it work to link one field with the other field with Website URL. – IamSJ Jan 24 '14 at 5:56
I don't think I understand what you are trying to do. Is field2_link something like a text field saying google.com? – Wrought_steel Jan 24 '14 at 6:01
The link field is created using a ACF [addon] (github.com/Jeradin/acf-website-field). The fields created using the addon works fine if I just publish it as <?php the_field('field2_link'); ?> and the other field <?php the_field('field1_details'); ?> separately. – IamSJ Jan 24 '14 at 6:10
field2_link has multiple inputs. What do you see when you display <?php the_field('field2_link'); ?> – Wrought_steel Jan 24 '14 at 6:17
I have updated the question with output for each of my attempt. – IamSJ Jan 24 '14 at 7:49

I think your URL is blank because you are simply not printing the result. You can either store the URL in a variable and echo it later:

<?php $myURL = get_field('field2_link'); ?>
<a href="<?php echo $myURL; ?>">

or echo it directly:

<a href="<?php ECHO get_field('field2_link'); ?>">

Either way you need to use the echo "function" to print the results.

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