Variable Not Working Inside is_author() Array

Question

I'm using a plugin (User Groups) to separate out users into, well, groups, and I need to figure out a way to create a conditional to check if an author is in a certain group. So, using get_term_by and get_objects_in_term, I was able to build a string of author IDs. See below:

$taxonomy = 'user-group';
$taxonomy_group_name = 'author-group';
$taxonomy_group_id = get_term_by('slug' , $taxonomy_group_name, $taxonomy, 'OBJECT');
$taxonomy_group_ids = get_objects_in_term($taxonomy_group_id->term_id, $taxonomy);
$taxonomy_id_list = implode(',', $taxonomy_group_ids);

So, I can take the list stored in $taxonomy_id_list and echo it out and get a string that looks like the below:

1,2,3,4,5,6,7

For the conditional, I should then be able to say:

if(is_author(array($taxonomy_id_list))) { }

But that doesn't work. If I paste the raw list into the array, it works as it should, but if I try to use the variable inside the array, the conditional does not work.

What am I missing? Why wouldn't that variable work?

Answer 1

You've converted $taxonomy_id_list to a comma separated string then shoved that string into an array. Your array now looks like

array(
  "1,2,3,4"
);

That is not going to match any author ID.

You are misunderstanding what implode does. This--1,2,3,4,5,6,7-- is a set of integers. If place in the array like this-- array(1,2,3,4,5,6,7)-- you get an array with 7 arguments. If you implode the IDs and put that into the array you have this-- array("1,2,3,4,5,6,7")-- an array with one argument.

Just skip this step: $taxonomy_id_list = implode(',', $taxonomy_group_ids); $taxonomy_group_ids, if it implodes the way you say, is already the array you need. There is no need to implode it only to try to reconvert it to an array.